document.write( "Question 1075099: Please help me solve the problem.I will appreciate your solution.
\n" ); document.write( "Question 1.\r
\n" ); document.write( "\n" ); document.write( " The weight of a certain type of chicken, when ready for the market, follows a normal distribution with mean 1.0 kg and a standard deviation of 0.20 kg. Find the probability that a chicken weighs less than 1.50 kilogram.
\n" ); document.write( "

Algebra.Com's Answer #689812 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
mean is 1 kg.
\n" ); document.write( "standard deviation is .2 kg.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "you want probability that the chicken weighs less than 1.5 kg.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "z-score = (x-m)/s\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x = 1.5 kg
\n" ); document.write( "m = 1 kg
\n" ); document.write( "s = .2 kg.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "formula becomes z = (1.5 - 1) / .2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "result is z = 2.5\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "probability of a z-score less than 2.5 is equal to .9938\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "in other words, the vast majority of the chickens will weight less than 1.5 kg if the mean is 1.0 kg and the standard deviation is .2 kg.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "here's the results using z-scores and using raw scores.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the results are the same, as they should be.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"$$$\"\r<BR\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"$$$\"\n" ); document.write( "
\n" );