document.write( "Question 1075071: If interest is earned at the rate of 5%, compounded annually, how long will it take an
\n" ); document.write( "investment of $10,000 to grow to $15,000
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Algebra.Com's Answer #689761 by addingup(3677)\"\" \"About 
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15,000 = 10,000(1+0.05)^t
\n" ); document.write( "divide both sides by 10,000:
\n" ); document.write( "1.5 = 1.05^t
\n" ); document.write( "rewrite, 1.5 = 3/2
\n" ); document.write( "log(1.05)^t = log(3/2)
\n" ); document.write( "t*log(1.05) = log(3/2)
\n" ); document.write( "t = (log(3/2))/(log 1.05)
\n" ); document.write( "t = log_1.05(3/2) = ~8.3 years\r
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