document.write( "Question 1075054: I) a (f) b = a/b – 2(b f a)
\n" ); document.write( "II) 3 (f) 1 = -7/9
\n" ); document.write( "III) 2 (f) 1 = ?
\n" ); document.write( "In the equations above, the function of (f) remains unchanged. What does the question mark stand for in the third equation?
\n" ); document.write( "a) -2/3, b)-1/3, c) 2/3, d)1, e)3
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #689752 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
The purpose for (I) must have been to show how the OPERATION (f) is supposed to work.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The purpose of (II) seems unnecessary other than to help to be sure we have used the operation as defined in (I) correctly.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Following the definition for f demonstrated in (I), choice (b) seems to be the result for (2 f 1); .\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "III.\r
\n" ); document.write( "\n" ); document.write( "2f1=2/1-2(1f2)\r
\n" ); document.write( "\n" ); document.write( "=2-2(1/2-2(2f1))\r
\n" ); document.write( "\n" ); document.write( "=2-1+4(2f1)\r
\n" ); document.write( "\n" ); document.write( "2f1=2-1+4(2f1)\r
\n" ); document.write( "\n" ); document.write( "2f1=1+4(2f1)\r
\n" ); document.write( "\n" ); document.write( "0=1+3(2f1)\r
\n" ); document.write( "\n" ); document.write( "-1=3(2f1)\r
\n" ); document.write( "\n" ); document.write( "-1/3=2f1
\n" ); document.write( "Corresponding to choice b.
\n" ); document.write( "
\n" );