document.write( "Question 1075054: I) a (f) b = a/b – 2(b f a)
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document.write( "II) 3 (f) 1 = -7/9
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document.write( "III) 2 (f) 1 = ?
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document.write( "In the equations above, the function of (f) remains unchanged. What does the question mark stand for in the third equation?
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document.write( "a) -2/3, b)-1/3, c) 2/3, d)1, e)3
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Algebra.Com's Answer #689752 by josgarithmetic(39617)![]() ![]() ![]() You can put this solution on YOUR website! The purpose for (I) must have been to show how the OPERATION (f) is supposed to work.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The purpose of (II) seems unnecessary other than to help to be sure we have used the operation as defined in (I) correctly.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Following the definition for f demonstrated in (I), choice (b) seems to be the result for (2 f 1); .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "III.\r \n" ); document.write( "\n" ); document.write( "2f1=2/1-2(1f2)\r \n" ); document.write( "\n" ); document.write( "=2-2(1/2-2(2f1))\r \n" ); document.write( "\n" ); document.write( "=2-1+4(2f1)\r \n" ); document.write( "\n" ); document.write( "2f1=2-1+4(2f1)\r \n" ); document.write( "\n" ); document.write( "2f1=1+4(2f1)\r \n" ); document.write( "\n" ); document.write( "0=1+3(2f1)\r \n" ); document.write( "\n" ); document.write( "-1=3(2f1)\r \n" ); document.write( "\n" ); document.write( "-1/3=2f1 \n" ); document.write( "Corresponding to choice b. \n" ); document.write( " |