document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1075032>Question 1075032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Diesel Inc. is making frames for a new product being launched at the end of the year. To keep the weight down, the area of the frame should be 18 cm^2. The inside of the frame has to be 11 cm by 6 cm. What should the width of the frame be?\r<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #689719 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=689719\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x is the width<BR>\n" );
document.write( "(11+x)(6+x), the outside dimensions, cannot be greater than 84 cm^2, because 84-66=18 cm^2<BR>\n" );
document.write( "66+17x+x^2 not greater than 84<BR>\n" );
document.write( "x^2+17x-18 < =0<BR>\n" );
document.write( "(x+18)(x-1) < =0<BR>\n" );
document.write( "x=1 cm width answer.<BR>\n" );
document.write( "12 x 7 is 84 cm^2, and that is 18 cm more than 66 cm.<BR>\n" );
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