document.write( "Question 1074902: Find the foci of the ellipse whose major axis has endpoints $(0,0)$ and $(13,0)$ and whose minor axis has length 12.\r
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Algebra.Com's Answer #689707 by KMST(5328)\"\" \"About 
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The center of that ellipse is the midpoint of the major axis,
\n" ); document.write( "half way between (0,0) and (13,0) on line y=0.
\n" ); document.write( "The coordinates of that midpoint are the averages of the coordinates of the vertices.
\n" ); document.write( "The midpoint is (6.5,0) , and that is the center of the ellipse.
\n" ); document.write( "The distance from the center to each vertex is called the semi-major axis and represented as \"a\" .
\n" ); document.write( "In this case \"a=6.5\" .
\n" ); document.write( "Half of the minor axis is called the semi-minor axis and is represented with \"b\" .
\n" ); document.write( "That is the distance from the center to each co-vertex.
\n" ); document.write( "In this case \"b=12%2F2=6\" .
\n" ); document.write( "The distance from the center to each focus is represented with \"c\" ,
\n" ); document.write( "and is related to \"a\" and \"b\" by \"a%5E2=b%5E2%2Bc%5E2\" .
\n" ); document.write( "In this case \"6.5%5E2=6%5E2%2Bc%5E2\" .
\n" ); document.write( "Solving for \"c\" :
\n" ); document.write( "\"6.5%5E2-6%5E2=c%5E2\"
\n" ); document.write( "A calculator can do that, but I don't need one
\n" ); document.write( "\"%286.5%2B6%29%29%286.5-6%29=c%5E2\"
\n" ); document.write( "\"0.5%2A12.5=c%5E2\"
\n" ); document.write( "\"6.25=c%5E2\"
\n" ); document.write( "\"c=sqrt%286.25%29\"
\n" ); document.write( "\"c=2.5\" .
\n" ); document.write( "That is the distance from center (6.5,0) to each focus.
\n" ); document.write( "The foci are on the same line as the vertices, line y=0,
\n" ); document.write( "on either side of the center,
\n" ); document.write( "so the x-coordinate of one focus is \"6.5-2.5=4\" ,
\n" ); document.write( "and the x-coordinate of the other focus is \"6.5%2B2.5=9\" .
\n" ); document.write( "So, the foci are \"highlight%28%22%28+4+%2C+0+%29+%2C+%289+%2C+0+%29%22%29\" .
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