document.write( "Question 1075001: an airplane takes 5 hours to travel a distance of 4200 miles with the wind. The return trip take 6 hours against the wind. Find the speed of the plane in still air and speed of the wind. \n" ); document.write( "
Algebra.Com's Answer #689683 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! speed * time=distance \n" ); document.write( "plane is traveling with the wind at 4200/5=840 \n" ); document.write( "s+w=840; on the way back it is 4200/6=700 \n" ); document.write( "s-w=700. Add the two \n" ); document.write( "2s=1540 \n" ); document.write( "s=770 mph is speed of plane in still air \n" ); document.write( "w=70 mph speed of wind. \n" ); document.write( " |