document.write( "Question 94675: KEEP GETTING THESE WRONG - HELP PLEASE\r
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document.write( "Need to solve:
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document.write( "log9(1/3)=y \r
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document.write( "Need to simplify:\r
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document.write( "e^x * 4e^2x+1 (the 2x+1 is all in exponent)
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document.write( "Thanks
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document.write( "LLO \n" );
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Algebra.Com's Answer #68967 by Nate(3500) ![]() You can put this solution on YOUR website! log9(1/3)=y \n" ); document.write( "log9(3^-1)=y \n" ); document.write( "-log9(3)=y \n" ); document.write( "3=9^-y \n" ); document.write( "-log10(3)/log10(9)=y \n" ); document.write( "-log10(3)/log10(3^2)=y \n" ); document.write( "-log10(3)/[2*log10(3)]=y \n" ); document.write( "-1/2=y \n" ); document.write( " \n" ); document.write( "~~~~~~~~~~~~~~ \n" ); document.write( "e^x * 4e^(2x + 1) \n" ); document.write( "4(e^x)e^(2x + 1) \n" ); document.write( "4e^(x + 2x + 1) \n" ); document.write( "4e^(3x + 1) \n" ); document.write( " |