document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1074671>Question 1074671</A>: <I><SPAN STYLE=\"word-break: break-all;\"> \" A machine produces bolts with an average of 0.51 inch and standard deviation of 0.01 inch.<BR>\n" );
document.write( "a.) What percentage of the total production would posses bolt diameter from 0.48 to 0.54?<BR>\n" );
document.write( "b.) What wil be the diameter if the total production percentage is 78.23% to the right of -Z.?\"<BR>\n" );
document.write( "thank you. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #689611 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=689611\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> z=(x-mean)/sd<BR>\n" );
document.write( "the first is the probability |z|<3. That is 99.73%.<BR>\n" );
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document.write( "I'm not clear about the wording of the second part.<BR>\n" );
document.write( "78.23% will have a z value from (-infinity to z=0.78)<BR>\n" );
document.write( "If a bolt has a diameter of 0.5178 in, it is at the 78.23% ile of all bolts. </SPAN>\n" );
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