document.write( "Question 1074901: Find k if x^3+6x^2+kx+12 is divisible by (x+4) \n" ); document.write( "
Algebra.Com's Answer #689564 by Edwin McCravy(20067)\"\" \"About 
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document.write( "Since x³+6x²+kx+12 is divisible by (x+4),\r\n" );
document.write( "if we divide by x+4 by synthetic division\r\n" );
document.write( "we should have a remainder of 0.\r\n" );
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document.write( "To divide by x+4 by synthetic division we \r\n" );
document.write( "use the opposite signed version -4\r\n" );
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document.write( "-4|1     6     k      12\r\n" );
document.write( "  |     -4    -8  -4k+32 \r\n" );
document.write( "   1     2   k-8  -4k+44\r\n" );
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document.write( "The remainder must = 0\r\n" );
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document.write( "                  -4k+44 = 0\r\n" );
document.write( "                     -4k = -44\r\n" );
document.write( "                       k = 11\r\n" );
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document.write( "Edwin
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