document.write( "Question 1074830: I have a quiz tomorrow, and I don't quite understand the \"ratio\" thing. Can you help explain how to do this problem? Thanks.\r
\n" ); document.write( "\n" ); document.write( "The ratio of corresponding linear measures of two similar cones is 3 to 4. The smaller cone has a volume of about 18 inches. Find the volume of of the larger cone, and round the answer to the nearest tenth, if necessary.
\n" ); document.write( "

Algebra.Com's Answer #689495 by josgarithmetic(39623)\"\" \"About 
You can put this solution on YOUR website!
That ratio means that if radius and height for the smaller cone is r and h, then for the larger cone, they are (4/3)r and (4/3)h.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "VOLUME, SMALL CONE
\n" ); document.write( "\"%281%2F3%29h%2Api%2Ar%5E2=18\", cubic inches\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%281%2F3%29pi%2A%28hr%5E2%29=18\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "VOLUME, LARGE CONE
\n" ); document.write( "\"%281%2F3%29%284%2F3%29h%2Api%2A%28%284%2F3%29r%29%5E2=V\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%281%2F3%29pi%2A%28%284%2F3%29h%29%2A%284%2F3%29%5E2%2Ar%5E2=V\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"%281%2F3%29pi%2Ahighlight_green%28%284%2F3%29%5E3%29%2Ahr%5E2=V\"\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "To go from the small cone volume to the large cone volume, multiply the small cone's volume by \"highlight_green%28%284%2F3%29%5E3%29\".\r
\n" ); document.write( "\n" ); document.write( "\"V=18%2A%284%2F3%29%5E3\"
\n" ); document.write( "
\n" );