document.write( "Question 1074789: An express bus travels a certain 250-mi route in 1.0 h less time than it takes a local bus to travel a 240-mi route. Find the speed of each bus if the speed of the local is 10 mi/h less than that of the express \n" ); document.write( "
Algebra.Com's Answer #689485 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
Let n be the speed of the local bus. Then the express bus would be n+10. So:
\n" ); document.write( "240/n-250/(n+10)=1
\n" ); document.write( "240n+2400-250n=nē+10n
\n" ); document.write( "nē+20n-2400=0
\n" ); document.write( "(n+60)(n-40)=0
\n" ); document.write( "n=40 or -60
\n" ); document.write( "The local bus travels 40 mph; the express bus travels 50 mph. ☺☺☺☺ \n" ); document.write( "
\n" );