document.write( "Question 1074819: use log_(5)2=0.4307 and log_(5)3= 0.6826 to approximate the value of log_(5)54\r
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Algebra.Com's Answer #689475 by MathTherapy(10806)\"\" \"About 
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use log_(5)2=0.4307 and log_(5)3= 0.6826 to approximate the value of log_(5)54\r
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\"log+%285%2C+2%29+=+0.4307\"		\"log+%285%2C+3%29+=+0.6826\"\r\n" );
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document.write( "\"log+%285%2C+54%29+=+0.4307\" ======> \"log+%285%2C+%282+%2A+27%29%29\" ======> \"log+%285%2C+%282+%2A+3%5E3%29%29\" ======> \"log+%285%2C+2%29+%2B+log+%285%2C+3%5E3%29\"\r\n" );
document.write( "\"log+%285%2C+2%29+%2B+3+%2A+log+%285%2C+3%29\" 	\r\n" );
document.write( "0.4307 + 3(0.6826) -------- Substituting 0.4307 for \"log+%285%2C+2%29\", and 0.6826 for \"log+%285%2C+3%29\"\r\n" );
document.write( "\"highlight_green%28matrix%281%2C3%2C+log+%285%2C+54%29%2C+%22=%22%2C+2.4785%29%29\"
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