document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1074819>Question 1074819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> use log_(5)2=0.4307 and log_(5)3= 0.6826 to approximate the value of log_(5)54\r<BR>\n" );
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document.write( "thank you </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #689468 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=689468\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The log5 (6)=log 5 (2*3)=log 5(2)+log 5 (3)<BR>\n" );
document.write( "That is 1.1133<BR>\n" );
document.write( "log 5 (54)=log 5 (9*6)=log 5(9)+log 5(6)<BR>\n" );
document.write( "But log 5(9)=log 5(3^2)=2 log 5(3)=1.3652<BR>\n" );
document.write( "log 5 (6)=1.1133<BR>\n" );
document.write( "The approximate answer is 1.3652+1.1133=2.4785 ANSWER<BR>\n" );
document.write( "5^2.4785=54.00 </SPAN>\n" );
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