document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1074814>Question 1074814</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solving exponential and logarithmic equations. <BR>\n" );
document.write( "Solve the equation. Then check for extraneous solutions. 2(3)exponent 2x = 5 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #689466 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=689466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2*3^(2x)=5.  This is how I interpret the equation.  <BR>\n" );
document.write( "3^(2x)=2.5<BR>\n" );
document.write( "2x log 3=log 2.5<BR>\n" );
document.write( "2x=log (2.5)/log (3)<BR>\n" );
document.write( "2x=0.8340<BR>\n" );
document.write( "x=0.4170<BR>\n" );
document.write( "3^(0.8340)=2.5 as a check </SPAN>\n" );
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