document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1074782>Question 1074782</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve for the rational inequality and find the interval. <BR>\n" );
document.write( "((3x-3) /(4-2x)) is more than or equal to 0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #689446 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=689446\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  Solve for the rational inequality and find the interval. <BR>\n" );
document.write( "f(x) >= ((3x-3) /(4-2x)) is more than or equal to 0 <BR>\n" );
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document.write( "f(x) = 0 when 3x-3 = 0 ; or x = 1<BR>\n" );
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document.write( "Comment::: f(x) > 0 when (3x-3)and (4-2x) have the same sign<BR>\n" );
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document.write( "If 3x-3 < 0 and 4-2x < 0, x < 1 and x > 2 (impossible)<BR>\n" );
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document.write( "If 3x-3 > 0 and 4-2x > 0, x > 1 and x < 2 ; (1,2)<BR>\n" );
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document.write( "Interval Solution:: [1,2)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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