document.write( "Question 1074737: A rectangular garden is fenced on three sides, and the house forms the fourth side of the rectangle.
\n" ); document.write( "Given that the total length of the fence is 80m show that the area, A, of the garden is given by the formula A=y(80-2y), where you is the distance from the house to the end of the garden.
\n" ); document.write( "Given that the area is a maximum for this length of fence, find the dimensions of the enclosed garden, and the area which is enclosed.
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Algebra.Com's Answer #689400 by josgarithmetic(39617)\"\" \"About 
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y, length from end of garden to house\r
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\n" ); document.write( "\n" ); document.write( "Two of the sides sum to \"y%2By=2y\". The side opposite the house must finish the length of the fence material of 80; so \"80-2y\" is this length.\r
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\n" ); document.write( "\n" ); document.write( "The two dimensions are \"y\" and \"80-2y\".
\n" ); document.write( "Area \"A=y%2880-2y%29\".\r
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\n" ); document.write( "\n" ); document.write( "Maximum area is when the rectangle becomes square shaped.
\n" ); document.write( "Since only three sides are to be used for the fence around the garden, each side is \"80%2F3=26%262%2F3\" meters.
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