document.write( "Question 1074160: Identify the z-score that corresponds with the Middle 47% of the distribution.
\n" ); document.write( "There is a mean score of 91 and and Standar Deviation of 5 and it is a normal distribution
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Algebra.Com's Answer #689300 by Fombitz(32388)\"\" \"About 
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47% in the middle leaves 53% for the left and right tails.
\n" ); document.write( "So the left tail contains 26.5%.
\n" ); document.write( "Find z so that \"P%28z%29=0.265\".
\n" ); document.write( "Using EXCEL NORMSINV function,
\n" ); document.write( "\"z=-0.62801\"
\n" ); document.write( "So then,
\n" ); document.write( "\"%28X-91%29%2F5=-0.62801\"
\n" ); document.write( "Now solve for X.
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