document.write( "Question 1074623: given: f(x)=(1/4)^x. how do I write down the equation of f^-1(x) in the form y=... \n" ); document.write( "
Algebra.Com's Answer #689275 by Theo(13342)![]() ![]() You can put this solution on YOUR website! start with f(x) = (1/4)^x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "set y = f(x) and the equation becomes y = (1/4)^x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "replace y with x and x with y and the equation becomes x = (1/4)^y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "now you want to solve for y.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = (1/4)^y if and only if log(1/4)(x) = y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your equation becomes y = log(1/4)(x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "set y = f-1(x) and the equation becomes f-1(x) = log(1/4)(x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the graph of both equations is shown below. \n" ); document.write( "since they are inverse equations, they are reflections about the equation of y = x.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "they are inverse equations if (x,y) in f(x) is equal to (y,x) in f-1(x).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the intersection of the both graphs with a line perpendicular to the line y = x shows this to be true.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the red curve is the normal equation and the blue curve is the inverse equation.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the reflection of the point (-1.448,7.448) in the normal equation is the point (7.448,-1.448) in the inverse equation, confirming that they are inverse equations.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "in general, if you start with y = bx, and you want to find the inverse equation, then replace x with y and y with x to get the equation x = by\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "this is true if and only if y = logb(x)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the inverse equation to y = bx is therefore y = logb(x).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "here's a nice reference on logarithmix and exponential functions you might find useful.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "http://www.themathpage.com/aprecalc/logarithmic-exponential-functions.htm\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |