document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1074621>Question 1074621</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A,B,C have to supply an order of 100 pens. A,B,C make a pen in 2,3,4 hrs respectively. In how many days they will complete the work if each one make a complete pen himself without the help of others. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #689269 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=689269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> in 1 hour<BR>\n" );
document.write( "A makes 1/2 pen<BR>\n" );
document.write( "B makes 1/3 pen<BR>\n" );
document.write( "C makes 1/4 pen<BR>\n" );
document.write( "in x hours, A makes x/2, B makes x/3 and C makes x/4 pens<BR>\n" );
document.write( "In x hours, 13x/12 pens are made, x((1/2)+(1/3)+(1/4))<BR>\n" );
document.write( "if 13x/12=100<BR>\n" );
document.write( "13x=1200<BR>\n" );
document.write( "x=92.3 pens.<BR>\n" );
document.write( "There can't be fractional pens, so look at 92 hours first<BR>\n" );
document.write( "A will make 46 pens completely and no more<BR>\n" );
document.write( "B will make 30 pens and is part way through the 31st.<BR>\n" );
document.write( "C will make 23 pens completely and no more<BR>\n" );
document.write( "That is 99 pens.<BR>\n" );
document.write( "In the 93rd hour, A will make another half pen and C another 1/4 pen, but B will finish the 31st pen, and there will be 100 pens.  <BR>\n" );
document.write( "93 hours is 3 days and 21 hours. or 3 7/8 days. </SPAN>\n" );
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