document.write( "Question 1074446: A right angled triangle with hypotenuse 20cm. A square 6cm placed in the right angle of the triangle. The hypothenuse touches the top right corner of the square.
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document.write( "What is length of other two sides?\r
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document.write( "I started usi g similar triangles and called base (x+6) and height (y+6) getting
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document.write( "y=36/x. Then use Pythagoras. But can't simplify the complicated algebra I get after that. \r
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document.write( "Can anyone help? \n" );
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Algebra.Com's Answer #689248 by Fombitz(32388) You can put this solution on YOUR website! .\n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "By Pythagoras, \n" ); document.write( " \n" ); document.write( "By similar triangles, \n" ); document.write( " \n" ); document.write( "So, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Substituting, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( " \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( ". \n" ); document.write( "Graphing finds two positive solutions, \n" ); document.write( " \n" ); document.write( "with corresponding x values, \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "So then the lengths of the other sides are, \n" ); document.write( " \n" ); document.write( " |