document.write( "Question 1074578: A concert audience of 400 people consists of adults, students, and children. The ticket prices are $40 for adults, $20 for students, and $10 for children. The total amount of money taken in was $10,600. The numbers of children tickets sold is 200 less than the number of adults and student tickets in total. How many adults, students, and children are in attendance? \n" ); document.write( "
Algebra.Com's Answer #689226 by ikleyn(52794)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( "A concert audience of 400 people consists of adults, students, and children. The ticket prices are $40 for adults, $20 for students, \n" ); document.write( "and $10 for children. The total amount of money taken in was $10,600. The numbers of children tickets sold is 200 less \n" ); document.write( "than the number of adults and student tickets in total. How many adults, students, and children are in attendance? \n" ); document.write( "~~~~~~~~~~~~~~~~~~~~~~~~\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let A = # of adults tickets, S = # of students tickets.\r\n" ); document.write( "\r\n" ); document.write( "Then the number of children tickets is A + S - 200.\r\n" ); document.write( "\r\n" ); document.write( "You have these equations\r\n" ); document.write( "\r\n" ); document.write( " A + S + (A+S-200) = 400, (1)\r\n" ); document.write( "40A + 20S + 10*(A+S-200) = 10600. (2)\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and write in the standard form\r\n" ); document.write( "\r\n" ); document.write( " 2A + 2S = 600, (1')\r\n" ); document.write( "50A + 30S = 12600. (2')\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Or even simpler\r\n" ); document.write( "\r\n" ); document.write( " A + S = 300, (1'')\r\n" ); document.write( "5A + 3S = 1260 (2'')\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From (1''), express A = 300-S and substitute it into (2''). You will get\r\n" ); document.write( "\r\n" ); document.write( "5*(300-S) + 3S = 1260.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "From this point, please complete the solution on your own.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |