document.write( "Question 1074533: Joshua is twice as old as his brother. Four years ago he was four times as old. Find the ages now. \n" ); document.write( "
Algebra.Com's Answer #689197 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! J is 2x years old today \n" ); document.write( "brother is x years old today \n" ); document.write( "2x-4=4(x-4), the four years ago situation \n" ); document.write( "2x-4=4x-16 \n" ); document.write( "2x=12 \n" ); document.write( "x=6 \n" ); document.write( "Joshua is 12 and his brother is 6. \n" ); document.write( "Four years ago, Joshua was 8 and his brother was 2. \n" ); document.write( " |