document.write( "Question 1074462: Please help me this question
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document.write( "y=13-4x
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document.write( "3x+2y=16
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document.write( "What is substitution \n" );
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Algebra.Com's Answer #689124 by addingup(3677)![]() ![]() You can put this solution on YOUR website! y = 13-4x this is the value of y. We will substitute in the next equation. First, set the next equation in the same format, subtract 3x from both sides: \n" ); document.write( "3x+2y = 16 \n" ); document.write( "2y = 16-3x now in this equation substitute for y: \n" ); document.write( "2(13-4x) = 16-3x Distribute the 2 over the terms inside parenthesis (Distributive Properties of multiplication): \n" ); document.write( "26-8x = 16-3x Subtract 16 and add 8x on both sides: \n" ); document.write( "26-16-8x+8x = 16-16-3x+8x \n" ); document.write( "10 = 5x flip the equation, we want the variable on the left (it doesn't change anything): \n" ); document.write( "5x = 10 divide both sides by 5 \n" ); document.write( "x = 2 \n" ); document.write( "Now solve for y: \n" ); document.write( "y = 13-4x \n" ); document.write( "y = 13-4(2) \n" ); document.write( "y = 13-8 \n" ); document.write( "y = 5 \n" ); document.write( "------------------ \n" ); document.write( "Check: \n" ); document.write( "3x+2y = 16 \n" ); document.write( "3(2)+2(5) = 16 \n" ); document.write( "6+10 = 16 Correct\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |