document.write( "Question 1074453: Water is flowing into a conical reservoir 25.0 m deep and 10.0 m across the top, at a rate of 16.0 m3/min. How fast is the surface rising when the water is 10.0 m deep? \n" ); document.write( "
Algebra.Com's Answer #689123 by Alan3354(69443)\"\" \"About 
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Water is flowing into a conical reservoir 25.0 m deep and 10.0 m across the top, at a rate of 16.0 m3/min. How fast is the surface rising when the water is 10.0 m deep?
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\n" ); document.write( "Assuming 10 m is the diameter, r = 5
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\n" ); document.write( "Vol = pi*r^2*h/3
\n" ); document.write( "Find r in terms of h:
\n" ); document.write( "For 0 <= h <= 25,
\n" ); document.write( "r/h = 5/25
\n" ); document.write( "r = h/5
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\n" ); document.write( "\"Vol+=+pi%2A%28h%5E2%2F25%29%2Ah%2F3+=+pi%2Ah%5E3%2F75\"
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\n" ); document.write( "dVol/dt = pi*h^2/25*dh/dt = 16
\n" ); document.write( "dh/dt = 400/(pi*h^2)
\n" ); document.write( "At h = 10,
\n" ); document.write( "dh/dt = 4/pi meters/minute\r
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