document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1074356>Question 1074356</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write each expression as the logarithm of a single number or expression. assume that all variables represent positive numbers. \r<BR>\n" );
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document.write( "3 in 2 + 2 in 3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #689039 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=689039\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 in 2 + 2 in 3<BR>\n" );
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document.write( "It's LN, for natural log, not in<BR>\n" );
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document.write( "= 3ln(2) + 2ln(3)<BR>\n" );
document.write( "= ln(2^3) + ln(3^2)<BR>\n" );
document.write( "= ln(8) + ln(9)<BR>\n" );
document.write( "= ln(72)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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