document.write( "Question 1074311: A courier service promises that 80% of deliveries will reach their destinations within 12 hours.what is the probability that of the 7 parcels sent at random times only one is delivered late? \n" ); document.write( "
Algebra.Com's Answer #689005 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
binomial formula is p(x) = p^x * q^(n-x) * c(n,x)\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "p is the probability of occurrence.
\n" ); document.write( "p is the probability of no occurrence = 1 - p.
\n" ); document.write( "x is the number of occurrences.
\n" ); document.write( "(n-x) is the number of non-occurrences.
\n" ); document.write( "c(n,x) is the combination formula for number of ways you can get x out of n without regard to order.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the probability of occurrence here would be the probability that the package is being delivered late.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "since 80% arrive within 12 hours, then 20% must not arrive within 12 hours.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "therefore, p = .2 and q = .8\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "p means the probability the package will be late.
\n" ); document.write( "q means the probability the paqckage will be on time.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if at least 6 out of 7 arrive on time, this means that at most 1 arrives late.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "this means that either 0 arrive later or 1 arrives late.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "therefore, you want p(0) + p(1).\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "p(0) = .2^0 * .8^7 * c(7,0) = 1 * .2097152 * 1 = .2097151
\n" ); document.write( "p(1) = .2^1 * .8^6 * c(7,1) = .2 * .262144 * 7 = .3670016\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the total probability of p(0) + p(1) = .5767526\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the following pictures shows all the probabilities from x = 0 to x = 7\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "their sum has to be equal to 1, as it is.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"$$$\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "the numbers shown for p(1) and p(2) are rounded a little more than the numbers i showed you above, but they are the same numbers.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );