document.write( "Question 1074244: Twice the sums of the width and the length of a desk top is 102 inches. The difference between 3 times the width and twice the length is 8 inches. Find the dimension of the desk top. \n" ); document.write( "
Algebra.Com's Answer #688941 by addingup(3677) You can put this solution on YOUR website! w+w+l+l = 102; 2w+2l = 102; w+l = 51; w = 51-l \n" ); document.write( "3w-2l = 8 \n" ); document.write( "3(51-l)-2l = 8 \n" ); document.write( "153-3l-2l = 8 \n" ); document.write( "-5l = -145 \n" ); document.write( "l = 29 \n" ); document.write( "So now we know the length. Let's find the width. Take one of the equations, any one. I'll use the first one, since I used the second to solve for l: \n" ); document.write( "2w+2l = 102 \n" ); document.write( "2w+2(29) = 102 \n" ); document.write( "2w+58 = 102 \n" ); document.write( "2w = 44 \n" ); document.write( "w = 22 \n" ); document.write( "------------------------- \n" ); document.write( "Check: \n" ); document.write( "1st equation \n" ); document.write( "2w+2l = 102 \n" ); document.write( "2(22)+2(29) = 102 \n" ); document.write( "44+58 = 102 Correct \n" ); document.write( "2nd equation \n" ); document.write( "3w-2l = 8 \n" ); document.write( "3(22)-2(29) = 8 \n" ); document.write( "66-58 = 8 Also correct. \n" ); document.write( "Happy learning, \n" ); document.write( "John \n" ); document.write( " |