document.write( "Question 1074244: Twice the sums of the width and the length of a desk top is 102 inches. The difference between 3 times the width and twice the length is 8 inches. Find the dimension of the desk top. \n" ); document.write( "
Algebra.Com's Answer #688941 by addingup(3677)\"\" \"About 
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w+w+l+l = 102; 2w+2l = 102; w+l = 51; w = 51-l
\n" ); document.write( "3w-2l = 8
\n" ); document.write( "3(51-l)-2l = 8
\n" ); document.write( "153-3l-2l = 8
\n" ); document.write( "-5l = -145
\n" ); document.write( "l = 29
\n" ); document.write( "So now we know the length. Let's find the width. Take one of the equations, any one. I'll use the first one, since I used the second to solve for l:
\n" ); document.write( "2w+2l = 102
\n" ); document.write( "2w+2(29) = 102
\n" ); document.write( "2w+58 = 102
\n" ); document.write( "2w = 44
\n" ); document.write( "w = 22
\n" ); document.write( "-------------------------
\n" ); document.write( "Check:
\n" ); document.write( "1st equation
\n" ); document.write( "2w+2l = 102
\n" ); document.write( "2(22)+2(29) = 102
\n" ); document.write( "44+58 = 102 Correct
\n" ); document.write( "2nd equation
\n" ); document.write( "3w-2l = 8
\n" ); document.write( "3(22)-2(29) = 8
\n" ); document.write( "66-58 = 8 Also correct.
\n" ); document.write( "Happy learning,
\n" ); document.write( "John
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