document.write( "Question 1074041: Please answer this is really hard. The observed angles of a quadrilateral after station and side adjusmtments are: Angle DBA=30 Degrees angle CBD=48 Degrees angle BCA=59 Degrees and angle DCA =21 degrees. Compute the angles BDA,DAC and DAB \n" ); document.write( "
Algebra.Com's Answer #688916 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
I do not know what was meant by \"station and side adjustments.\"
\n" ); document.write( "I imagine the quadrilateral (with its diagonals) looks like this,
\n" ); document.write( " or a rotated and/or flipped version.
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\n" ); document.write( "\"DBA=30%5Eo\" , \"CBD=48%5Eo\" , \"BCA=59%5Eo\" , and \"DCA+=21%5Eo\" .
\n" ); document.write( "So, \"BCD=BCA%2BDCA=59%5Eo%2B21%5Eo=80%5Eo\" and \"CBA=CBD%2BDBA=48%5Eo%2B30%5Eo=78%5Eo\"
\n" ); document.write( "Also, \"DXA=CXB=180%5Eo-59%5Eo-48%5Eo=73%5Eo\" and
\n" ); document.write( "\"BAC=180%5Eo-59%5Eo-78%5Eo=43%5Eo\" based on the sum of angle measures for triangles BXC and BAC respectively.
\n" ); document.write( "
\n" ); document.write( "With that, I can compute approximate measures for BDA, DAC and DAB.
\n" ); document.write( "It takes quite a bit of coordinate geometry calculations, and I do not get an exact value, but it is the best I can do so far.
\n" ); document.write( "For ease of calculations, I set coordinates for points C and B as
\n" ); document.write( "\"C%280%2C0%29\" and \"B%2810%2C0%29\" .
\n" ); document.write( "Then I find coordinates for \"D%28x%5BD%5D%2Cy%5BD%5D%29\" and \"A%28x%5BA%5D%2Cy%5BA%5D%29\" .
\n" ); document.write( "\"system%28y%5BD%5Dcot%2880%5Eo%29=x%5BD%5D%2Cy%5BD%5Dcot%2848%5Eo%29=10-x%5BD%5D%29\" --> --> -->
\n" ); document.write( "Approximate value: \"D%281.638%2C9.287%29\"
\n" ); document.write( "Similarly for A,
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\n" ); document.write( "Approximate value: \"A%287.387%2C12.294%29\" .
\n" ); document.write( "(I have my computer keep more digits in these calculations, because they are intermediate calculations, and I round at the end).
\n" ); document.write( "The slope of line DA is the tangent of the angle DA makes with the x-axis (or with any horizontal line).
\n" ); document.write( "It is \"%2812.294-9.287%29%2F%287.387-1.638%29=3.006%2F5.749=0.5230\" .
\n" ); document.write( "That is the tangent of approximately a \"27.6%5Eo\" angle.
\n" ); document.write( "Since line BD makes a \"-48%5Eo\" angle with the horizontal,
\n" ); document.write( "the measure of angle BDA is about \"BDA=27.6%5Eo%2B48%5Eo=75.6%5Eo\" .
\n" ); document.write( "\"DAC=59%5Eo-27.6%5Eo=31.4%5Eo\" based on the angles DA and AC make with the x-axis.
\n" ); document.write( "Or, \"DAC=180%5Eo-73%5Eo-27.6%5Eo=31.4%5Eo\" based on the sum of angle measures for triangle ADX.
\n" ); document.write( "Finally, \"DAB=DAC%2BBAC=31.4%5Eo%2B43%5Eo=74.4%5Eo\" .
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