document.write( "Question 1074154: 2-log2x=log(x/18) \n" ); document.write( "

Algebra.Com's Answer #688904 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+2+-+log%28+2x+%29+=+log%28+x%2F18+%29+\"$
\n" ); document.write( "Convert $\"+2+\"$ to a base 10 log
\n" ); document.write( " $\"+2+=+log%28+100+%29+\"$
\n" ); document.write( "------------------------
\n" ); document.write( " $\"+log%28+100+%29+-+log%28+2x+%29+=+log%28+x%2F18+%29+\"$
\n" ); document.write( " $\"+log%28+100%2F%282x%29%29+=+log%28+x%2F18+%29+\"$
\n" ); document.write( " $\"+100%2F%282x%29+=+x%2F18+\"$
\n" ); document.write( " $\"+50%2Fx+=+x%2F18+\"$
\n" ); document.write( " $\"+50%2A18+=+x%5E2+\"$
\n" ); document.write( " $\"+x%5E2+=+900+\"$
\n" ); document.write( " $\"+x+=+30+\"$
\n" ); document.write( "---------------------
\n" ); document.write( "Only the positive square root is allowed since
\n" ); document.write( "any log with base 10 cannot result in a negative number
\n" ); document.write( "-----------------------
\n" ); document.write( "check answer:
\n" ); document.write( " $\"+log%28+100+%29+-+log%28+2x+%29+=+log%28+x%2F18+%29+\"$
\n" ); document.write( " $\"+log%28+100+%29+-+log%28+2%2A30+%29+=+log%28+30%2F18+%29+\"$
\n" ); document.write( " $\"+log%28+100+%29+-+log%28+60+%29+=+log%28+5%2F3+%29+\"$
\n" ); document.write( " $\"+log%28+100+%29+-+log%28+60+%29+=+log%28+5+%29+-+log%28+3+%29+\"$
\n" ); document.write( " $\"+2+-+1.77815+=+.69897+-+.477121+\"$
\n" ); document.write( " $\"+.22185+=+.221849+\"$
\n" ); document.write( "close enough
\n" ); document.write( " \n" ); document.write( "

\n" );