document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1074159>Question 1074159</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A motorboat goes 15 miles downstream at its top speed and then turns around and returns 15 miles upstream at its top speed. The trip upstream took twice as long as the trip downstream. If the boats' top speed is 10 mph in still water, how fast is the current?\r<BR>\n" );
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document.write( "D=Rt rule is confused again. <BR>\n" );
document.write( "Please help me with this. <BR>\n" );
document.write( "Thank you.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #688880 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=688880\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let c be the speed of the current. Then<BR>\n" );
document.write( "15/10-c=2(15/10+c)<BR>\n" );
document.write( "15/10-c=30/10+c<BR>\n" );
document.write( "300-30c=150+15c<BR>\n" );
document.write( "45c=150<BR>\n" );
document.write( "c=3.3333 mph as the speed of the current. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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