document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=94538>Question 94538</A>: <I><SPAN STYLE=\"word-break: break-all;\"> divide\r<BR>\n" );
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document.write( "6p - 18/9p (divided by) 3p - 9/p^2 + 2p </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #68888 by </B><A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><B>jayanthihemkos@yahoo.com(87)</B></A><img src=\"/images/stars/stars-08.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jayanthihemkos@yahoo.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=68888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 6p - 18/9p (divided by) 3p - 9/p^2 + 2p\r<BR>\n" );
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document.write( "6(p-3)/9p (divided by ) 3(p -3) /p(p+2)\r<BR>\n" );
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document.write( "2(p-3)/ 3p (multiplied by ) p(p+2)/3(p-3) take inverse of 3(p-3) /p(p+2)\r<BR>\n" );
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document.write( "(p-3) gets cancelled\r<BR>\n" );
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document.write( "p gets cancelled\r<BR>\n" );
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document.write( " now we have 2(p+2)/9\r<BR>\n" );
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document.write( "(2p+4)/9 is the solution.\r<BR>\n" );
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