document.write( "Question 1074145: Uta invests an amount into a compound interest investment account that pays 6% a year. After six years, she withdraws her total balance of $500. Using the formula , how much money did Uta initially invest? \n" ); document.write( "
Algebra.Com's Answer #688869 by josmiceli(19441)\"\" \"About 
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A = P (1 + r/n) (nt)\r
\n" ); document.write( "\n" ); document.write( "Where:\r
\n" ); document.write( "\n" ); document.write( "A = the future value of the investment/loan, including interest
\n" ); document.write( "P = the principal investment amount (the initial deposit or loan amount)
\n" ); document.write( "r = the annual interest rate (decimal)
\n" ); document.write( "n = the number of times that interest is compounded per year
\n" ); document.write( "t = the number of years the money is invested or borrowed for
\n" ); document.write( "( lifted from the calculatorsite )
\n" ); document.write( "--------------------------------------
\n" ); document.write( "\"+A+=+500+\"
\n" ); document.write( "\"+P+\" is the original investment
\n" ); document.write( "\"+r+=+.06+\"
\n" ); document.write( "\"+n+=+1+\"
\n" ); document.write( "\"+t+=+6+\"
\n" ); document.write( "------------------------------
\n" ); document.write( "\"+500+=+P%2A%28+1+%2B+.06%2F1+%29%5E%28+1%2A6+%29+\"
\n" ); document.write( "\"+500+=+P%2A1.06%5E6+\"
\n" ); document.write( "\"+P+=+500+%2F+%28+1.06%5E6+%29+\"
\n" ); document.write( "\"+P+=+500+%2F+1.4185+\"
\n" ); document.write( "\"+P+=+352.485+\"
\n" ); document.write( "Uta originally invested $352.49
\n" ); document.write( "check the math
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