document.write( "Question 1074124: the length of a rectangle is 2 less than 3 times the width .if the width is tripled while the length is decreased by 2,the new perimeter is 34 more than half the original perimeter.find the original dimensions. \n" ); document.write( "

Algebra.Com's Answer #688850 by josgarithmetic(39617) $\"\"$ $\"About$

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Original Rectangle\r
\n" ); document.write( "\n" ); document.write( "Dimensions w and 3w-2\r
\n" ); document.write( "\n" ); document.write( "Perimeter p,
\n" ); document.write( " $\"p=2%283w-2%29%2B2w\"$ \r
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\n" ); document.write( "\n" ); document.write( "New Rectangle\r
\n" ); document.write( "\n" ); document.write( "Dimensions 3w and 3w-2-2=3w-4\r
\n" ); document.write( "\n" ); document.write( "Perimeter description,
\n" ); document.write( " $\"34%2Bp%2F2=2%283w-4%29%2B2%2A3w\"$ \r
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\n" ); document.write( "\n" ); document.write( "Simplify the two equations.
\n" ); document.write( "Solve the two equations as a system for w and evaluate length.
\n" ); document.write( "(perimeter p can also be solved for.) \n" ); document.write( "

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