document.write( "Question 1074080: the length of a rectangle is 7cm more than twice the width. the perimeter is 86cm. find the dimensions of the rectangle.\r
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document.write( "i tried this
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document.write( "86=2(7)+2w
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document.write( "86-14=2w
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document.write( "72/2=2w/2
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document.write( "but i keep getting the wrong answer \n" );
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Algebra.Com's Answer #688816 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! the length of a rectangle is 7cm more than twice the width. \n" ); document.write( "L = 2w+7 \n" ); document.write( " the perimeter is 86cm. find the dimensions of the rectangle \n" ); document.write( "2L + 2W = 86 \n" ); document.write( "simplify, divide by 2 \n" ); document.write( "L + w = 43 \n" ); document.write( "replace L with (2w+7) \n" ); document.write( "(2w+7) + w = 43 \n" ); document.write( "3w = 43 - 7 \n" ); document.write( "3w = 36 \n" ); document.write( "w = 36/3 \n" ); document.write( "w = 12 cm is the width \n" ); document.write( "then \n" ); document.write( "L = 2(12) + 7 \n" ); document.write( "L = 31 cm is the length \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "Check the solution with these dimensions \n" ); document.write( "2(31) + 2(12) = \n" ); document.write( "62 + 24 = 86 \n" ); document.write( " |