document.write( "Question 1074021: The ratio of interior and exterior angles of a polygon is 6:4. Find the sum of the angles of the polygon.
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Algebra.Com's Answer #688793 by KMST(5328)\"\" \"About 
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THE SHORT WAY:
\n" ); document.write( "The ratio given means that it is a polygon
\n" ); document.write( "with congruent angles, and at least 5 sides, because
\n" ); document.write( "if the angles were not all congruent,
\n" ); document.write( "there would be two or more different ratios,
\n" ); document.write( "and for 3- and 4-sided polygons with congruent angles,
\n" ); document.write( "the ratios are 1:2 and 1:1 respectively.
\n" ); document.write( "So, for this polygon, At every vertex,
\n" ); document.write( "the ratio of exterior to interior angle,
\n" ); document.write( "and the ratio of the sums of exterior and interior angles is 6:4.
\n" ); document.write( "The sum of all the exterior angles of any polygon is \"360%5Eo\" ,
\n" ); document.write( "If \"x\"= the sum of all interior angles,
\n" ); document.write( "\"x%2F360%5Eo=6%2F4\" ---> \"x=6%2A360%5Eo%2F4\" ---> \"highlight%28x=540%5Eo%29\" .
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\n" ); document.write( "ANOTHER WAY (with insights):
\n" ); document.write( "The interior and exterior angles at each vertex are supplementary,
\n" ); document.write( "meaning that their measures add up to \"180%5Eo\" .
\n" ); document.write( "So, a larger interior angle would be paired with a smaller exterior angle.
\n" ); document.write( "If the ratio is 6:4 for the pair of angles at every vertex,
\n" ); document.write( "all interior angles in that polygon have the same measure,
\n" ); document.write( "and the polygon is equiangular, just like a regular polygon
\n" ); document.write( "Except for an equilateral triangles (with just 3 angles)
\n" ); document.write( "and rectangles or squares (with just 4 angles),
\n" ); document.write( "the exterior angles are smaller than the interior ones
\n" ); document.write( "in all regular polygons.
\n" ); document.write( "So, if \"E\" is the measure of each exterior angle in degrees,
\n" ); document.write( "\"%286%2F4%29%2AE\" is the measier of each interior angle,
\n" ); document.write( "and \"%286%2F4%29E%2BE=180\" .
\n" ); document.write( "Solving for \"E\":
\n" ); document.write( "\"%286%2F4%2B1%29E=180\"
\n" ); document.write( "\"%2810%2F4%29E=180\"
\n" ); document.write( "\"E=180%2A4%2F10\"
\n" ); document.write( "\"E=72\"
\n" ); document.write( "The exterior angles are the change in direction
\n" ); document.write( "as each vertex as you go around the polygon,
\n" ); document.write( "So their measures add up to a whole turn, or \"360%5Eo\" .
\n" ); document.write( "If the polygon has \"n\" angles,
\n" ); document.write( "then the sum of the measures of the exterior angles (in degrees) is
\n" ); document.write( "\"72n=360\" --> \"n=360%2F72\" --> \"n=5\" .
\n" ); document.write( "So, the polygon is a pentagon.
\n" ); document.write( "The formula for the sum of interior angles for a polygon with
\n" ); document.write( "\"n\" sides (and \"n\" angles) is
\n" ); document.write( "\"%28n-2%29%2A180%5Eo\" .
\n" ); document.write( "For \"n=5\" , that sum is
\n" ); document.write( "\"%285-2%29%2A180%5Eo=3%2A180%5Eo=highlight%28540%5Eo%29\" .
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