document.write( "Question 94557: Can someone please help me.
\n" ); document.write( "Sum of 2 numbers is 71. The second is 6 more than 4 times the first. What are the 2 numbers.\r
\n" ); document.write( "\n" ); document.write( "Thanks \n" ); document.write( "
Algebra.Com's Answer #68879 by jayanthihemkos@yahoo.com(87)\"\" \"About 
You can put this solution on YOUR website!
Sum of 2 numbers is 71. The second is 6 more than 4 times the first. What are the 2 numbers.\r
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\n" ); document.write( "\n" ); document.write( "Let first number = x\r
\n" ); document.write( "\n" ); document.write( "The second number = 4x+6\r
\n" ); document.write( "\n" ); document.write( "THe sum of the two numbers = 71\r
\n" ); document.write( "\n" ); document.write( "x+(4x+6) = 71\r
\n" ); document.write( "\n" ); document.write( "x+4x+6 = 71\r
\n" ); document.write( "\n" ); document.write( "5x+6 = 71\r
\n" ); document.write( "\n" ); document.write( "5x+6-6 = 71-6\r
\n" ); document.write( "\n" ); document.write( "5x = 65\r
\n" ); document.write( "\n" ); document.write( "5x/5 = 65/5\r
\n" ); document.write( "\n" ); document.write( "x = 13\r
\n" ); document.write( "\n" ); document.write( "CHECK\r
\n" ); document.write( "\n" ); document.write( "x+4x+6 = 71\r
\n" ); document.write( "\n" ); document.write( "13+4(13) +6 =71\r
\n" ); document.write( "\n" ); document.write( "71 = 71 \r
\n" ); document.write( "\n" ); document.write( "LHS = RHS\r
\n" ); document.write( "\n" ); document.write( "Hence x = 13 is the solution\r
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