document.write( "Question 1074054: In a jar of coins, there are 30 fewer quarters than dimes. The value of the dimes equals the value of the quarters. How many dimes are in the jar.
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Algebra.Com's Answer #688776 by ikleyn(52908)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "From the condition, you have these two equations\r\n" );
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document.write( "Q = D -30,    (1)\r\n" );
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document.write( "10D = 25Q.    (2)\r\n" );
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document.write( "Substitute (1) into (2), and you will get\r\n" );
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document.write( "10D = 25*(D - 30)  --->  10D = 25D - 750  --->  15D = 750  --->  D = \"750%2F15\" = 50.\r\n" );
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document.write( "Answer.  50 dimes and 50-30 = 20 quarters.\r\n" );
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\n" ); document.write( "\n" ); document.write( "For coin problems and their detailed solutions see the lessons in this site:\r
\n" ); document.write( "\n" ); document.write( "    - Coin problems\r
\n" ); document.write( "\n" ); document.write( "    - More Coin problems\r
\n" ); document.write( "\n" ); document.write( "    - Solving coin problems without using equations\r
\n" ); document.write( "\n" ); document.write( "    - Kevin and Randy Muise have a jar containing coins\r
\n" ); document.write( "\n" ); document.write( "    - Typical coin problems from the archive\r
\n" ); document.write( "\n" ); document.write( "    - Solving coin problems mentally by grouping without using equations\r
\n" ); document.write( "\n" ); document.write( "    - Santa Claus helps solving coin problem\r
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\n" ); document.write( "\n" ); document.write( "Read them attentively and become an expert in this field.\r
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\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
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\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this online textbook under the topic \"Coin problems\".\r
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