document.write( "Question 1074037: Find the equation for the line that passes through the point (-2,4) abd that is parallel to the line with the equation y-3=1/2 (x-2)
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Algebra.Com's Answer #688770 by addingup(3677)\"\" \"About 
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y-3 = 1/2(x-2)
\n" ); document.write( "y = 3+1/2x-1
\n" ); document.write( "y = 1/2x+2
\n" ); document.write( "now we have the equation in slope-intercept form y = mx+b
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\n" ); document.write( "Slope: 1/2 - ordered pair: (-2, 4)
\n" ); document.write( "y-y_1 = m(x-x_1)
\n" ); document.write( "y-4 = 1/2(x-(-2))
\n" ); document.write( "y-4 = 1/2(x+2)
\n" ); document.write( "y-4 = 1/2x+1
\n" ); document.write( "y = 1/2x+5 This is the equation of your line. Notice it has the same slope, 1/2, so both lines are parallel.\r
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