document.write( "Question 1073930: A model rocket is launched with an initial velocity of 180 ft/s. The height, h, in feet, of the rocket t seconds after the launch is given by
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document.write( "h = −16t2 + 180t.
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document.write( "How many seconds after launch will the rocket be 280 ft above the ground? Round to the nearest hundredth of a second.
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document.write( ".......... (smaller value)
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document.write( "............(larger value) \n" );
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Algebra.Com's Answer #688725 by jorel1380(3719)![]() ![]() You can put this solution on YOUR website! By your equation; \n" ); document.write( "-16tē+180t=280 \n" ); document.write( "16tē-180t+280=0 \n" ); document.write( "4tē-45t+70=0 \n" ); document.write( "Using the quadratic formula, we get two roots of 9.38540223912 and 1.86459776088, or 9.4 and 1.9 seconds after launch. ☺☺☺☺ \n" ); document.write( " |