document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1073876>Question 1073876</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The length of a rectangle is the same as the length of a square.  The length of this rectangle is 4cm more than 3 times the width of the rectangle.  The area of the square is 66cm^2 more than the area of the rectangle.<BR>\n" );
document.write( "Find the length and width of the rectangle.<BR>\n" );
document.write( "Length x width/area of square = (3w+4)^2 = 9w^2+24w+16 which equals 66cm^2 more than the area of the rectangle.<BR>\n" );
document.write( "And I'm stuck!  Please help.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #688715 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=688715\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let w be the width of the rectangle. Then its length would be 3w+4. The area of the square would be (3w+4)². So:<BR>\n" );
document.write( "w(3w+4)+66=(3w+4)²<BR>\n" );
document.write( "3w²+4w+66=9w²+24w+16<BR>\n" );
document.write( "6w²+20w-50=0<BR>\n" );
document.write( "3w²+10w-25=0<BR>\n" );
document.write( "(3w-5)(w+5)=0<BR>\n" );
document.write( "w=5/3 or -5<BR>\n" );
document.write( "The width is 1-2/3 cm, the length is 9 cm. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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