document.write( "Question 1073903: for 100 ft edging materials,
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Algebra.Com's Answer #688684 by rothauserc(4718)\"\" \"About 
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let l be the length and w be the width, then
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\n" ); document.write( "2l + 2w = 100
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\n" ); document.write( "1) l + w = 50
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\n" ); document.write( "2) Area(A) of rectangle = l * w
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\n" ); document.write( "solve equation 1 for l and substitute for l in equation 2
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\n" ); document.write( "l = 50 - w
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\n" ); document.write( "A = (50 - w) * w = 50w - w^2
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\n" ); document.write( "To find max area, we take the first derivative and set it equal to zero since A is the equation for a parabola that opens downward
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\n" ); document.write( "A' = 50 - 2w
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\n" ); document.write( "50 -2w = 0
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\n" ); document.write( "w = 25 and l = 25
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\n" ); document.write( "max A = 25 * 25 = 625 square feet
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\n" ); document.write( "circumference(C) of a circle = pi * diameter(d)
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\n" ); document.write( "100 = (22/7) * d
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\n" ); document.write( "d = (100 * 7) / 22 = 31.8182
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\n" ); document.write( "radius(r) = 31.8182 / 2 = 15.9091
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\n" ); document.write( "Area of circle = pi * r^2 = (22/7) * (15.9091)^2 = 795.4555 square feet
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