document.write( "Question 1073869: box have 4 red, 3 green balls. another box have 2 red, 1 green. ball selected from each bag. find probability both are different color
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Algebra.Com's Answer #688651 by Fombitz(32388) $\"\"$ $\"About$

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\n" ); document.write( "There'll be a higher probability it gets answered.
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\n" ); document.write( "So look at the possible outcomes.
\n" ); document.write( "You choose a red ball from the first bag, then choose a green ball from the second.
\n" ); document.write( "Or you choose a green ball from the first bag, then choose a red ball from the second.
\n" ); document.write( "The first case P(RG),
\n" ); document.write( " $\"P%28R%5B1%5D%29=4%2F7\"$
\n" ); document.write( " $\"P%28G%5B2%5D%29=1%2F3\"$
\n" ); document.write( "So,
\n" ); document.write( " $\"P%28RG%29=%284%2F7%29%281%2F3%29=4%2F21\"$
\n" ); document.write( "The second case P(GR),
\n" ); document.write( " $\"P%28G%5B1%5D%29=3%2F7\"$
\n" ); document.write( " $\"P%28R%5B2%5D%29=2%2F3\"$
\n" ); document.write( "So,
\n" ); document.write( " $\"P%28GR%29=%283%2F7%29%282%2F3%29=6%2F21\"$
\n" ); document.write( "So then together,
\n" ); document.write( " $\"P=P%28RG%29%2BP%28GR%29\"$
\n" ); document.write( " $\"P=4%2F21%2B6%2F21\"$
\n" ); document.write( " $\"P=10%2F21\"$
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