document.write( "Question 1034815: On Monday, Lassister began monitoring the size of a bacteria colony. He noted that the mass of the colony grew from 5 grams at 8am to 6.5 grams at 2 PM.
\n" ); document.write( "a) find the value for k and write an exponential growth function that estimates the mass M of the bacteria colony t hours after 8 AM Monday.
\n" ); document.write( "b) What will the mass be at 6 PM Monday?
\n" ); document.write( "c) To the nearest hour, at what time will the mass of the growing colony reach 15 grams?\r
\n" ); document.write( "\n" ); document.write( "please explain.
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Algebra.Com's Answer #688618 by jorel1380(3719)\"\" \"About 
You can put this solution on YOUR website!
The formula for the growth rate is FA(final amount)=IA(initial amount)*(1+r(growth rate))^t. So:
\n" ); document.write( "a)6.5=5*(1+r)^6
\n" ); document.write( "1.3=(1+r)^6
\n" ); document.write( "1.3^.166666667=1+r
\n" ); document.write( "1+r=1.0446975079232772081587297735437
\n" ); document.write( "r=.0446975079232772081587297735437 as the growth rate of the bacteria. So:
\n" ); document.write( "M(1)=M(0)(1.044697508)^t
\n" ); document.write( "b)M=5*(1.044697508)^10
\n" ); document.write( "M=5*1.5484799527553624553339254907836=7.742399763776812276669627453918 gms. ☺☺☺☺
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