document.write( "Question 1073792: Two ships leave port at noon. One ship's speed is 15 km/h on a heading of 75 degree. The other ship's speed is 24 km/h on a heading of 155 degree. How far apart are they at 3pm and what is the bearing of each from the other? \n" ); document.write( "
Algebra.Com's Answer #688605 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Two ships leave port at noon. One ship's speed is 15 km/h on a heading of 75 degree. \n" ); document.write( " The other ship's speed is 24 km/h on a heading of 155 degree. \n" ); document.write( ": \n" ); document.write( "Find the distance they traveled in 3 hrs \n" ); document.write( "1st ship dist: 3 * 15 = 45 km \n" ); document.write( "2nd ship dist: 3 * 24 = 72 km \n" ); document.write( "Find the angle between the paths of these two ships. \n" ); document.write( "155 - 75 = 80 degrees between the two ship's paths. \n" ); document.write( ": \n" ); document.write( "How far apart are they at 3pm and what is the bearing of each from the other? \n" ); document.write( "Draw this out as triangle, use law the of cosines to find the distance between two ships \n" ); document.write( "a = distance between the ships \n" ); document.write( "A = 80 degrees \n" ); document.write( "b = 45 \n" ); document.write( "c = 72 \n" ); document.write( "a^2 = b^2 + c^2 - 2(bc)*cos(80) \n" ); document.write( "a^2 = 45^2 + 72^2 - 2(45*72)*.173648 \n" ); document.write( "You do the math, I got \n" ); document.write( "a = 78.00 km between the ships at 3 pm \n" ); document.write( ":\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |