document.write( "Question 1073783: A car travels 816 mi. A second car, traveling 3 mph faster than the first car, makes the same trip in 1 h less time. Find the speed of each car.
\n" ); document.write( "first car .......... mph
\n" ); document.write( "second car ......... mph \n" ); document.write( "

Algebra.Com's Answer #688581 by jorel1380(3719) $\"\"$ $\"About$

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Let n be the speed of the slower car. Then the faster car is going n+3. So:
\n" ); document.write( "816/n=816/(n+3) + 1
\n" ); document.write( "816(n+3)=816n+n²+3n
\n" ); document.write( "n²+3n-2448=0
\n" ); document.write( "(n+51)(n-48)=0
\n" ); document.write( "n=48 or -51
\n" ); document.write( "The first car travels at 48 mph; the second car travels at 51 mph. ☺☺☺☺ \n" ); document.write( "

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