document.write( "Question 1073587: The first and second terms of a geometric progression are cos θ and sin θ respectively.
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document.write( "(a) Find the common ration r and the third term of this geometric progression in terms of θ.
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document.write( "(b) Given that the first and third terms of this geometric progression and tan θ are three consecutive terms of an arithmetic progression, find the general solution for θ. Give your answer in radians correct to two decimal places.
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document.write( "(c) Suppose that 0 < r < 1. Find the sum to infinity of the geometric progression in this case. \n" );
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Algebra.Com's Answer #688502 by KMST(5328)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(a) The common ratio, \n" ); document.write( "one term divided by the term before. In this case \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The third term is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(b) So the first three terms of the arithmetic progression in this problem are \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The common difference is \n" ); document.write( " \n" ); document.write( "but it is also \n" ); document.write( " \n" ); document.write( "So, our equation is \n" ); document.write( " \n" ); document.write( "Solving: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "I am tired of writing \n" ); document.write( "I will abbreviate it as \n" ); document.write( "(It's what the teacher would call a change of variable). \n" ); document.write( "Now the equation is \n" ); document.write( " \n" ); document.write( "and I can solve it using the quadratic formula \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "That yields two solutions for \n" ); document.write( "The approximate values are \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "since both are between \n" ); document.write( "they both could be \n" ); document.write( "Using the inverse function of sine, in radians, I find that \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The inverse sine function gives you the solutions in quadrants 1 and 4, \n" ); document.write( "but we know that \n" ); document.write( "so that would give us two more solutions: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "for a total of 4 solutions, one per quadrant. \n" ); document.write( "There is an infinity number of other solutions, \n" ); document.write( "because adding an integer number \n" ); document.write( "you get a co-terminal angle that has the same values for all its trigonometric functions. \n" ); document.write( "So, the general solutions are \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "NOTE: \n" ); document.write( "There are other ways to write the solution. \n" ); document.write( "I could use \n" ); document.write( "I could use 3.14 for \n" ); document.write( "I could have two formulas if I consolidate quadrants, \n" ); document.write( "because \n" ); document.write( "(in one cumbersome expression) as \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "(c) The sum to infinity of a geometric progression \n" ); document.write( "with first term \n" ); document.write( " \n" ); document.write( "Is this part supposed to be connected to part (b)? \n" ); document.write( "I suppose so. This is almost as evil a problem as the high school comprehensive finals I used to have in Uruguay. \n" ); document.write( "We could conceive that \n" ); document.write( "That means quadrants 1 or 3 for a positive tangent, and \n" ); document.write( " \n" ); document.write( "Considering that and the solutions to part (b) above, \n" ); document.write( " \n" ); document.write( "but \n" ); document.write( "for a quadrant 3 angle, with \n" ); document.write( "Hopefully an approximate solution would be OK. \n" ); document.write( "In that case, using \n" ); document.write( "and \n" ); document.write( " |