document.write( "Question 1073587: The first and second terms of a geometric progression are cos θ and sin θ respectively.
\n" ); document.write( "(a) Find the common ration r and the third term of this geometric progression in terms of θ.
\n" ); document.write( "(b) Given that the first and third terms of this geometric progression and tan θ are three consecutive terms of an arithmetic progression, find the general solution for θ. Give your answer in radians correct to two decimal places.
\n" ); document.write( "(c) Suppose that 0 < r < 1. Find the sum to infinity of the geometric progression in this case.
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Algebra.Com's Answer #688502 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
\"cos%28theta%29\"= the first term in a geometric progression
\n" ); document.write( "\"sin%28theta%29\"= the second term term in the same geometric progression.
\n" ); document.write( "
\n" ); document.write( "(a) The common ratio, \"r\" in a geometric progression is the ratio of one term to the next,
\n" ); document.write( "one term divided by the term before. In this case
\n" ); document.write( "\"highlight%28r=sin%28theta%29%2Fcos%28theta%29=tan%28theta%29%29\"
\n" ); document.write( "
\n" ); document.write( "The third term is
\n" ); document.write( " .
\n" ); document.write( "
\n" ); document.write( "(b) So the first three terms of the arithmetic progression in this problem are
\n" ); document.write( "\"a%5B1%5D=cos%28theta%29\" ,
\n" ); document.write( "\"a%5B2%5D=sin%5E2%28theta%29%2Fcos%28theta%29\" and
\n" ); document.write( "\"a%5B3%5D=tan%28theta%29=sin%28theta%29%2Fcos%28theta%29\" .
\n" ); document.write( "The common difference is
\n" ); document.write( "\"d=a%5B2%5D-a%5B1%5D=sin%5E2%28theta%29%2Fcos%28theta%29-cos%28theta%29\" ,
\n" ); document.write( "but it is also
\n" ); document.write( "\"d=a%5B3%5D-a%5B2%5D=sin%28theta%29%2Fcos%28theta%29-sin%5E2%28theta%29%2Fcos%28theta%29\" .
\n" ); document.write( "So, our equation is
\n" ); document.write( " .
\n" ); document.write( "Solving:
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\"sin%5E2%28theta%29-cos%5E2%28theta%29=sin%28theta%29-sin%5E2%28theta%29\"
\n" ); document.write( "\"sin%5E2%28theta%29%2B1-cos%5E2%28theta%29=sin%28theta%29-sin%5E2%28theta%29%2B1\"
\n" ); document.write( "\"sin%5E2%28theta%29%2Bsin%5E2%28theta%29=sin%28theta%29-sin%5E2%28theta%29%2B1\"
\n" ); document.write( "\"sin%5E2%28theta%29%2Bsin%5E2%28theta%29%2Bsin%5E2%28theta%29=sin%28theta%29%2B1\"
\n" ); document.write( "\"3sin%5E2%28theta%29=sin%28theta%29%2B1\"
\n" ); document.write( "I am tired of writing \"sin%28theta%29\" so many times.
\n" ); document.write( "I will abbreviate it as \"x=sin%28theta%29\" for a while.
\n" ); document.write( "(It's what the teacher would call a change of variable).
\n" ); document.write( "Now the equation is
\n" ); document.write( "\"3x%5E2=x%2B1\" <---> \"3x%5E2-x-1=0\" ,
\n" ); document.write( "and I can solve it using the quadratic formula
\n" ); document.write( "\"x+=+%28-%28-1%29+%2B-+sqrt%28%28-1%29%5E2-4%2A3%2A%28-1%29%29%29%2F%282%2A3%29+\"
\n" ); document.write( "\"x+=+%281+%2B-+sqrt%281%2B12%29%29%2F6+\"
\n" ); document.write( "\"x+=+%281+%2B-+sqrt%2813%29%29%2F6+\" .
\n" ); document.write( "That yields two solutions for \"x=sin%28theta%29\" .
\n" ); document.write( "The approximate values are
\n" ); document.write( "\"x+=+%281%2Bsqrt%2813%29%29%2F6=about0.76759\" and
\n" ); document.write( "\"x+=+%281-sqrt%2813%29%29%2F6=about-0.43426\" .
\n" ); document.write( "since both are between \"-1\" and \"1\" ,
\n" ); document.write( "they both could be \"sin%28theta%29\" for some \"theta\" .
\n" ); document.write( "Using the inverse function of sine, in radians, I find that
\n" ); document.write( "\"sin%280.87508%29=%281%2Bsqrt%2813%29%29%2F6\" and
\n" ); document.write( "\"sin%28-0.44921%29=%281%2Bsqrt%2813%29%29%2F6\" .
\n" ); document.write( "The inverse sine function gives you the solutions in quadrants 1 and 4,
\n" ); document.write( "but we know that \"sin%28pi-theta%29=sin%28theta%29\" ,
\n" ); document.write( "so that would give us two more solutions:
\n" ); document.write( "\"3.14159-0.87508=2.26652\" in quadrant 2, and
\n" ); document.write( "\"3.14159-%28-0.44921%29=3.14159%2B0.44921=3.59081\" in quadrant 3,
\n" ); document.write( "for a total of 4 solutions, one per quadrant.
\n" ); document.write( "There is an infinity number of other solutions,
\n" ); document.write( "because adding an integer number \"k\" of whole turns to an angle,
\n" ); document.write( "you get a co-terminal angle that has the same values for all its trigonometric functions.
\n" ); document.write( "So, the general solutions are
\n" ); document.write( "\"highlight%28theta=0.88%2Bk2pi%29\"
\n" ); document.write( "\"highlight%28theta=2.27%2Bk2pi%29\"
\n" ); document.write( "\"highlight%28theta=-0.451%2Bk2pi%29\"
\n" ); document.write( "\"highlight%28theta=3.59%2Bk2pi%29\" .
\n" ); document.write( "
\n" ); document.write( "NOTE:
\n" ); document.write( "There are other ways to write the solution.
\n" ); document.write( "I could use \"2pi%2B%28-0.44921%29=5.83397\" for the quadrant 4 solution, if I di not like to see negative numbers.
\n" ); document.write( "I could use 3.14 for \"pi\", but then as {{k}}} increases the general solution would not be \"correct to two decimal places.\"
\n" ); document.write( "I could have two formulas if I consolidate quadrants,
\n" ); document.write( "because \"theta\" and \"pi-theta\" can be written
\n" ); document.write( "(in one cumbersome expression) as
\n" ); document.write( "\"pi%2F2+%2B-+%28theta-pi%2F2%29\" .
\n" ); document.write( "
\n" ); document.write( "(c) The sum to infinity of a geometric progression
\n" ); document.write( "with first term \"b\" and \"0%2Cr%2C1\" is
\n" ); document.write( "\"b%2F%281-r%29\" .
\n" ); document.write( "Is this part supposed to be connected to part (b)?
\n" ); document.write( "I suppose so. This is almost as evil a problem as the high school comprehensive finals I used to have in Uruguay.
\n" ); document.write( "We could conceive that \"0%3Cr=tan%28theta%29=sin%28theta%29%2Fcos%28theta%29%3C1\"
\n" ); document.write( "That means quadrants 1 or 3 for a positive tangent, and
\n" ); document.write( "\"sin%28theta%29%3Ccos%28theta%29\"--> \"sin%28theta%29%3Csqrt%282%29%2F2=about0.707\" .
\n" ); document.write( "Considering that and the solutions to part (b) above,
\n" ); document.write( "\"sin%28theta%29+=+%281%2Bsqrt%2813%29%29%2F6=about0.76759\" does not work,
\n" ); document.write( "but \"sin%28theta%29++=+%281-sqrt%2813%29%29%2F6=about-0.43426\" would work
\n" ); document.write( "for a quadrant 3 angle, with \"cos%28theta%29=+-+sqrt%281-sin%5E2%28theta%29%29\" .
\n" ); document.write( "Hopefully an approximate solution would be OK.
\n" ); document.write( "In that case, using \"r=tan%283.59081%29=0.48209\" ,
\n" ); document.write( "and \"b=cos%28theta%29=cos%283.59081%29=-0.90079\" , we get
\n" ); document.write( "\"sum=%28-0.90079%29%2F%281-0.48209%29=about\"\"highlight%28-1.739%29\" .
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