document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1073571>Question 1073571</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve the problem. You must write two equations with two variables and show steps to solve.\r<BR>\n" );
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document.write( "Anne and Nancy use a metal alloy that is 17% copper to make jewelery. How many ounces of an alloy that is 11% copper must be mixed with an alloy that is 22% copper to form 55 ounces of the desired alloy? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #688434 by </B><A HREF=/tutors/aboutme.mpl?userid=jorel1380><B>jorel1380(3719)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jorel1380><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=jorel1380><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=688434\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let n be the amount of 22% copper to be used, and m be the amount of 11% copper to be used. Then:<BR>\n" );
document.write( "n+m=55 and<BR>\n" );
document.write( ".22n+.11m=.17(55)<BR>\n" );
document.write( "So:<BR>\n" );
document.write( "n+m=55<BR>\n" );
document.write( "m=55-n<BR>\n" );
document.write( ".22n+.11(55-n)=9.35<BR>\n" );
document.write( ".11n+6.05=9.35<BR>\n" );
document.write( ".11n=3.3<BR>\n" );
document.write( "n=30<BR>\n" );
document.write( "m=25<BR>\n" );
document.write( "They need 30 oz. of 22% alloy, and 25 oz. of 11% alloy to make their jewelery. &#9786;&#9786;&#9786;&#9786; </SPAN>\n" );
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