document.write( "Question 1073630: Solve the system of linear equations by substitution. Check your solution. \r
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document.write( "4x + 2y = 0\r
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document.write( "y = 1/2x - 5 \n" );
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Algebra.Com's Answer #688426 by addingup(3677)![]() ![]() You can put this solution on YOUR website! 4x + 2y = 0 \n" ); document.write( "and \n" ); document.write( "y = 1/2x - 5 \n" ); document.write( "Thus: \n" ); document.write( "4x + 2(1/2x-5) = 0 \n" ); document.write( "4x + x-10 = 0 \n" ); document.write( "5x = 10 \n" ); document.write( "x = 2 \n" ); document.write( "Now solve for y: \n" ); document.write( "4(2) + 2y = 0 \n" ); document.write( "8+2y = 0 \n" ); document.write( "2y = -8 \n" ); document.write( "y = -4 \n" ); document.write( "-------------------- \n" ); document.write( "Check: \n" ); document.write( "4(2) + 2(-4) = 0 \n" ); document.write( "8 + (-8) = 0 \n" ); document.write( "8 - 8 = 0 Correct \n" ); document.write( " |