document.write( "Question 1073578: If \"+r%28x%29=+sqrt%28x%2B1%29-2+\"; find\r
\n" ); document.write( "\n" ); document.write( "A. r(x)<0
\n" ); document.write( "B. r(x)>0\r
\n" ); document.write( "\n" ); document.write( "I'm completely lot. I plugged in random values for x to get y. Like this:\r
\n" ); document.write( "\n" ); document.write( "When x=8; y=1\r
\n" ); document.write( "\n" ); document.write( "I'm not sure what to do from there...\r
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Algebra.Com's Answer #688380 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
It's easier to graph it.
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\n" ); document.write( "Or at the very least, solve for,
\n" ); document.write( "\"sqrt%28x%2B1%29-2=0\"
\n" ); document.write( "\"sqrt%28x%2B1%29=2%7D%7D%0D%0A%7B%7B%7Bx%2B1=4\"
\n" ); document.write( "\"x=3\"
\n" ); document.write( "Then you know the dividing line between positive and negative values.
\n" ); document.write( "Then you can divide the regions that are less than zero and those that are greater than zero.\r
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