document.write( "Question 1073563: Flying with the wind, a small plane flew 240 mi in 2 h. Against the wind, the plane could fly only 210 mi in the same amount of time. Find the rate of the plane in calm air and the rate of the wind. \n" ); document.write( "
Algebra.Com's Answer #688373 by ikleyn(52816)\"\" \"About 
You can put this solution on YOUR website!
.
\n" ); document.write( "
\r\n" );
document.write( "Let \"u\" be the speed of the plane at no wind (=same as in calm air), in mph.\r\n" );
document.write( "Let \"v\" be the speed of wind.\r\n" );
document.write( "\r\n" );
document.write( "Then the effective speed of the plane flying WITH the wind is (u+v) mph (relative to the ground).\r\n" );
document.write( "\r\n" );
document.write( "the effective speed of the plane flying AGAINST the wind is (u-v) mph (relative to the ground).\r\n" );
document.write( "\r\n" );
document.write( "According to the condition, \r\n" );
document.write( "the plane effective speed is \"240%2F2\" = 120 mph flying  with    the wind,\r\n" );
document.write( "and       effective speed is \"210%2F2\" = 105 mph flying  against the wind.\r\n" );
document.write( "\r\n" );
document.write( "It gives you two equations \r\n" );
document.write( "\r\n" );
document.write( "u + v = 120,    (1)\r\n" );
document.write( "u - v = 105.    (2)\r\n" );
document.write( "\r\n" );
document.write( "Add the two equations (both sides). You will get\r\n" );
document.write( "\r\n" );
document.write( "2u = 120 + 105 = 225.   Hence,  u = \"225%2F2\" = 112.5.\r\n" );
document.write( "\r\n" );
document.write( "Thus the speed of the plane at no wind is 112.5 mph.\r\n" );
document.write( "\r\n" );
document.write( "Next, from the equation (1) v = 120 - u = 120 - 112.5 = 7.5 mph.\r\n" );
document.write( "\r\n" );
document.write( "Thus the speed of the wind  is 7.5 mph.\r\n" );
document.write( "\r\n" );
document.write( "Answer.  The speed of the plane at no wind is 112.5 mph..\r\n" );
document.write( "\r\n" );
document.write( "         The speed of the wind  is 7.5 mph.\r\n" );
document.write( "\r\n" );
document.write( "Check.  The speed of the plane with the wind is 112.5 + 7.5 = 120 mph, and the flight time is \"240%2F120\" = 2 hours.\r\n" );
document.write( "\r\n" );
document.write( "        The speed of the plane against the wind is 112.5 - 7.5 = 105 mph, and the flight time is \"210%2F105\" = 2 hours.\r\n" );
document.write( "\r\n" );
document.write( "        Checks !\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "It is a typical \"tailwind and headwind\" word problem.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "See the lessons \r
\n" ); document.write( "\n" ); document.write( "    - Wind and Current problems \r
\n" ); document.write( "\n" ); document.write( "    - Wind and Current problems solvable by quadratic equations \r
\n" ); document.write( "\n" ); document.write( "    - Selected problems from the archive on a plane flying with and against the wind \r
\n" ); document.write( "\n" ); document.write( "in this site.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "In these lessons you will find the detailed solutions of many similar problems. \r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Learn how to solve similar problems once and for all.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Also, you have this free of charge online textbook in ALGEBRA-I in this site\r
\n" ); document.write( "\n" ); document.write( "    - ALGEBRA-I - YOUR ONLINE TEXTBOOK.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The referred lessons are the part of this textbook under the section \"Word problems\", the topic \"Travel and Distance problems\".\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );